20x^2=600

Solution for 20x^2=600 equation:

20x^2=600

We move all terms to the left:

20x^2-(600)=0

a = 20; b = 0; c = -600;
Δ = b2-4ac
Δ = 02-4·20·(-600)
Δ = 48000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{48000}=\sqrt{1600*30}=\sqrt{1600}*\sqrt{30}=40\sqrt{30}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-40\sqrt{30}}{2*20}=\frac{0-40\sqrt{30}}{40}
=-\frac{40\sqrt{30}}{40}
=-\sqrt{30}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+40\sqrt{30}}{2*20}=\frac{0+40\sqrt{30}}{40}
=\frac{40\sqrt{30}}{40}
=\sqrt{30}
$